QUESTION 1 In the diagram below, straight line PS is defined by 3y+2x=6 and cuts the x-axis at Q(3; 0). MQR is a straight line which meets PR at R(10; 4). N(6; -2) is a point on PS and RN is drawn. PÔR = 0. 1.1 17 M Gala O (3:0) Determine the gradient of PS. R(10:4) N(6-2) (2)
QUESTION 1 In the diagram below, straight line PS is defined by 3y+2x=6 and cuts the x-axis at Q(3; 0). MQR is a straight line which meets PR at R(10; 4). N(6; -2) is a point on PS and RN is drawn. PÔR = 0. 1.1 17 M Gala O (3:0) Determine the gradient of PS. R(10:4) N(6-2) (2)
Answer:
-2/3
Step-by-step explanation:
To determine the gradient of the line PS, we can rearrange the equation 3y + 2x = 6 into the slope-intercept form, y = mx + c, where m is the gradient.
Rearranging the equation:
3y + 2x = 6
3y = -2x + 6
y = (-2/3)x + 2
Comparing this equation with y = mx + c, we can see that the gradient (m) of line PS is -2/3.
Therefore, the gradient of line PS is -2/3.
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